c++ - How to retain 0s after decimal point, after converting string to double -


this question has answer here:

#include <iostream>  using namespace std;  int main() {     string str="-1.2300";     double d = stod(str);     cout<<d<<"\n"; }

output: -1.23

i expecting output following

-1.2300

if want, need use formatted output precision specifier:

printf("%.4f\n", d);

or specify precision cout:

cout.precision(4); cout << fixed << d << "\n";

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