arrays - Sorting opening hours in PHP -

i have array opening hours structured this:

array:7 [   "mon" => array [     "open" => null     "close" => null   ]   "tue" => array [     "open" => null     "close" => null   ]   "wed" => array [     "open" => "09:00"     "close" => "20:00"   ]   "thu" => array [     "open" => null     "close" => null   ]   "fri" => array [     "open" => "14:00"     "close" => "17:00"   ]   "sat" => array [     "open" => "12:00"     "close" => "15:00"   ]   "sun" => array [     "open" => "12:00"     "close" => "15:00"   ] ] 

i create structure this:

array [   array [         "mon" => array [           "open" => null           "close" => null         ]         "tue" => array [             "open" => null             "close" => null         ]     ]     array [         "wed" => array [             "open" => "09:00"             "close" => "20:00"         ]     ]     array [         "thu" => array [             "open" => null             "close" => null         ]     ]     array [         "fri" => array [             "open" => "14:00"             "close" => "17:00"         ]     ]     array [         "sat" => array [             "open" => "12:00"             "close" => "15:00"         ]         "sun" => array [             "open" => "12:00"             "close" => "15:00"         ]     ] ] 

where days same opening hours grouped long days in row. otherwise day should end itself.

i've been working on achieving in php , i've got far.

$hours = [];  $previousday = null;  foreach ($days $key => $day) {        if ($day === $previousday)     {         $hours[] = array($key => $day);      }     else      {         $hours[] = array($key => $day);      }      $previousday = $day;  }   

i'm stuck on how group days same opening hours in 1 array.

how below?

$result = array(); $previous = null; $idx = -1; foreach ($days $key => $day){     if($day !== $previous){         $idx++;     }     $result[$idx][$key] = $day;     $previous = $day; }