python - Tkinter - Code is executed without tkinter reacting -

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• button command being called automatically 2 answers

while trying create countdown timer, have ran problem. have based myself on bryan oakleys code (making countdown timer python , tkinter?) did not post whole code because quite long.

what want code do:

wait x amount of seconds, stored in wait , collected entry waite. next, want wait_button call countdown call. class create label in own tkinter window. after countdown (= x seconds delay) main function recalled , change flow.

what does:

the code executed without errors. countdown takes place, , flows changed, without second delay , without opening tkinter window.

any appreciated, looked on site did not find helped resolve problem.

stijn

def wait_button(self):      """this part of larger tkinter grid , called after pushing button"""      """wait set ammount of time before changing"""       self.flow = self.collect()      self.waite = int(self.waite.get())      countdown(self.flow, self.waite)      return()  class countdown():         def __init__(self, flow, waite):          self.master = tk()         self.label = label(self.master, text="", width=10)         self.label.pack()         self.remaining = waite         self.flow =  flow         self.counting(flow, self.remaining)      def counting(self, flow, remaining = none):          print(flow, "after init")         if remaining not none:             self.remaining = remaining          if int(self.remaining) <= 0:             self.master.destroy()             go = askinput(root)             go.change_now(flow)          else:             print(self.remaining, "-1")             self.label.configure(text="%d" % self.remaining)             self.remaining = self.remaining - 1             self.label.after(1000, self.counting(self.flow))  

solved tigerhawkt3.

"try replacing line after self.label.after(1000, lambda: self.counting(self.flow))"